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数学图形(1.45)毛雷尔玫瑰(Maurer rose)
阅读量:6695 次
发布时间:2019-06-25

本文共 1243 字,大约阅读时间需要 4 分钟。

毛雷尔玫瑰,也有的翻译是毛瑞尔,它是一种很漂亮的图形.玫瑰线的变异品种.

我没有找到其中文的解释,有兴趣可以看下.

Maurer rose of the rose r = sin() consists of the 360 lines successively connecting the above 361 points. Thus a Maurer rose is a  with  on a rose.

A Maurer rose can be described as a closed route in the . A walker starts a journey from the origin, (0, 0), and walks along a line to the point (sin(nd), d). Then, in the second leg of the journey, the walker walks along a line to the next point, (sin(n·2d), 2d), and so on. Finally, in the final leg of the journey, the walker walks along a line, from (sin(n·359d), 359d) to the ending point, (sin(n·360d), 360d). The whole route is the Maurer rose of the rose r = sin(). A Maurer rose is a since the starting point, (0, 0) and the ending point, (sin(n·360d), 360d), coincide.

相关软件参见:,使用自己定义语法的脚本代码生成数学图形.

vertices = 361t = from 0 to 360n = 2d = 39k = t*d*0.0174533x = sin(n*k)*cos(k)y = sin(n*k)*sin(k)r = 10x = x*ry = y*rz = z*r

 

vertices = 361t = from 0 to 360n = 6d = 71k = t*d*0.0174533x = sin(n*k)*cos(k) y = sin(n*k)*sin(k) r = 10 x = x*r y = y*r z = z*r

使用随机参数的代码:

vertices = 361t = from 0 to 360n = rand_int2(3, 12)d = rand_int2(1, 100)k = t*d*0.0174533x = sin(n*k)*cos(k) y = sin(n*k)*sin(k) r = 10 x = x*r y = y*r z = z*r

 

转载地址:http://tmpoo.baihongyu.com/

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